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Cambridge IGCSE Physics revision notes

Resistance Revision Notes

Cambridge IGCSE revision notes for Resistance.

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Resistance

CambridgeIGCSEPhysicsElectricity and magnetism

Complete revision guide 1 of 5

Resistance and Ohm's Law

Resistance quantifies how much a component opposes the flow of electric current. It is defined as the ratio of potential difference across the component to the current flowing through it. Ohm's law expresses this relationship mathematically as R = V/I, where R is resistance in ohms (Ω), V is potential difference in volts (V), and I is current in amperes (A). This fundamental relationship allows calculation of any one quantity if the other two are known.

Syllabus source

Section 3, Topic 4.2.4, page 29, objective 4.2.4.1

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What you should be able to do

  • ✓Define electrical resistance and its unit.
  • ✓State and use the formula relating resistance, potential difference, and current.
  • ✓Rearrange the formula to calculate potential difference or current when resistance and one other quantity are known.
  • ✓Understand the physical meaning of resistance in a circuit component.
  • ✓Apply the formula in numerical problems with correct units and significant figures.
1

Definition of Resistance

Electrical resistance is a measure of how much a component or material opposes the flow of electric current through it.

It is defined as the ratio of the potential difference (voltage) across the component to the current flowing through it.

Mathematically, resistance R is given by R = V / I, where V is the potential difference in volts (V) and I is the current in amperes (A).

  • Resistance is a scalar quantity measured in ohms (Ω).
  • 1 ohm (Ω) is the resistance when a potential difference of 1 volt causes a current of 1 ampere to flow.
2

Ohm's Law and Its Mathematical Form

Ohm's law states that, for many conductors at constant temperature, the current flowing through the conductor is directly proportional to the potential difference across it.

This relationship can be expressed as V = IR, where V is potential difference, I is current, and R is resistance.

From this, resistance can be calculated by rearranging the formula to R = V / I.

  • V (voltage) is measured in volts (V).
  • I (current) is measured in amperes (A).
  • R (resistance) is measured in ohms (Ω).
3

Using the Formula in Calculations

To calculate resistance, measure the potential difference across the component and the current through it, then use R = V / I.

To find potential difference, rearrange to V = IR.

To find current, rearrange to I = V / R (though this is beyond the current objective).

  • Always include units in calculations to ensure correctness.
  • Example: If V = 12 V and I = 3 A, then R = 12 V / 3 A = 4 Ω.
  • Common error: forgetting to convert units or mixing units leads to incorrect answers.
4

Physical Interpretation of Resistance

Resistance arises because electrons moving through a conductor collide with atoms, losing energy and slowing down the flow of charge.

Higher resistance means less current for a given potential difference.

Resistance depends on material, length, cross-sectional area, and temperature (covered in other objectives).

  • A resistor is a component designed to have a specific resistance.
  • Ohmic conductors obey Ohm's law; their resistance remains constant over a range of voltages and currents.

At-a-glance summary

Comparison table

StepPhysics DetailEvidenceExam Use
Define resistanceResistance is the ratio of voltage to current, R = V/IGiven in syllabus and textbooksRecall definition for AO1 questions
Use formulaCalculate resistance from measured V and IPractical measurements with voltmeter and ammeterApply formula in numerical problems
Rearrange formulaExpress V = IR to find voltageAlgebraic manipulationUse in calculations and problem solving
Interpret resistanceResistance opposes current flowMicroscopic explanation of collisionsExplain physical meaning in short answer questions
Include unitsResistance in ohms (Ω), voltage in volts (V), current in amperes (A)SI units standardEnsure correct units for full marks

Active recall

Quick check

1. What is the unit of resistance?

Ohm (Ω). It is the unit when 1 volt causes 1 ampere of current.

2. Calculate the resistance if the potential difference is 9 V and the current is 3 A.

R = V / I = 9 V / 3 A = 3 Ω.

3. If a resistor has a resistance of 5 Ω and a current of 2 A flows through it, what is the potential difference across it?

V = IR = 5 Ω × 2 A = 10 V.

Complete revision guide 2 of 5

Measuring Electrical Resistance Using a Voltmeter and Ammeter

This note explains how to measure the resistance of a component by setting up a circuit with a voltmeter and an ammeter, detailing the apparatus, method, calculations, and considerations for accuracy and safety.

Syllabus source

Section 3, Topic 4.2.4, page 29, objective 4.2.4.2

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What you should be able to do

  • ✓Understand how to connect an ammeter and voltmeter correctly in a circuit to measure current and voltage.
  • ✓Learn the step-by-step procedure to measure resistance experimentally.
  • ✓Apply Ohm's Law to calculate resistance from measured voltage and current.
  • ✓Recognise the importance of repeating measurements and controlling variables to improve accuracy.
  • ✓Identify common sources of error and methods to reduce uncertainty in resistance measurements.
1

Apparatus and Circuit Setup

To measure the resistance of a resistor, you need the following apparatus: a resistor (or component whose resistance is to be measured), a power supply (such as a battery or DC power supply), an ammeter, a voltmeter, connecting wires, and a switch.

Connect the circuit as follows: connect the ammeter in series with the resistor and the power supply. This arrangement allows the ammeter to measure the current flowing through the resistor.

Connect the voltmeter in parallel across the resistor. This means the voltmeter's two terminals connect to the two ends of the resistor, enabling it to measure the potential difference (voltage) across it.

  • Ammeter connected in series with the resistor to measure current (I).
  • Voltmeter connected in parallel across the resistor to measure voltage (V).
  • Power supply provides the driving voltage for current flow.
  • Switch included to control the circuit safely.
2

Procedure for Measuring Resistance

1. Assemble the circuit as described, ensuring all connections are secure.

2. Close the switch to allow current to flow through the circuit.

3. Record the current reading from the ammeter (in amperes, A). Note that the ammeter should have a low resistance to avoid affecting the circuit current significantly, but this is usually negligible for school experiments.

  • 4. Record the voltage reading from the voltmeter (in volts, V).
  • 5. Repeat the readings several times, possibly varying the voltage by adjusting the power supply if possible, to obtain multiple pairs of current and voltage values.
  • 6. Open the switch and disconnect the circuit after measurements are complete.
3

Calculations and Use of Ohm's Law

Ohm's Law states that the resistance R of a component is the ratio of the voltage V across it to the current I flowing through it:

R = V / I, where R is resistance in ohms (Ω), V is voltage in volts (V), and I is current in amperes (A).

To calculate resistance: substitute the measured voltage and current values into the formula. For example, if V = 6.0 V and I = 0.20 A, then: R = 6.0 V / 0.20 A = 30 Ω.

  • Always include units in calculations to ensure correctness.
  • If multiple readings are taken, calculate resistance for each pair and find an average to improve accuracy.
  • Be aware that some components do not have constant resistance; this method assumes the resistor behaves ohmically (constant resistance).
4

Improving Accuracy and Controlling Variables

To improve the reliability of the resistance measurement:

Take multiple readings of voltage and current and calculate an average resistance.

Ensure connections are tight to reduce contact resistance errors, which can affect readings especially at low resistance values.

  • Use a suitable range on the ammeter and voltmeter to get precise readings without overloading the instruments.
  • Keep the temperature of the resistor constant, as resistance can change with temperature.
  • Use a variable power supply to vary voltage and check if resistance remains constant, confirming ohmic behaviour.
  • Record uncertainties in measurements and consider them when reporting results.
5

Safety and Practical Considerations

Use low voltages to prevent overheating the resistor or damaging the meters.

Do not exceed the current rating of the resistor or ammeter to avoid damage or hazards.

Switch off the power supply before changing the circuit connections to prevent electric shock or short circuits.

  • Handle equipment carefully to avoid damage.
  • Ensure the voltmeter has a high resistance to prevent it from drawing significant current and affecting the circuit.
  • Check the polarity of meters before connecting to avoid incorrect readings or damage.

At-a-glance summary

Comparison table

StepPhysics DetailEvidenceExam Use
Connect ammeter in seriesAmmeter measures current flowing through resistorAmmeter reading shows current in amperesRequired to measure current for resistance calculation
Connect voltmeter in parallelVoltmeter measures potential difference across resistorVoltmeter reading shows voltage in voltsRequired to measure voltage for resistance calculation
Record readingsObtain current (I) and voltage (V) valuesData collected from metersUsed in calculations to find resistance
Calculate resistanceUse formula R = V / ISubstitute measured values into formulaDemonstrates understanding of Ohm's Law
Repeat measurementsReduce random errors and improve accuracyMultiple readings provide consistent dataShows good experimental technique

Active recall

Quick check

1. How should the ammeter be connected in the circuit to measure resistance?

The ammeter should be connected in series with the resistor to measure the current flowing through it.

2. What is the correct connection for the voltmeter when measuring resistance?

The voltmeter should be connected in parallel across the resistor to measure the voltage across it.

3. Write the formula to calculate resistance from voltage and current.

Resistance R = Voltage V divided by Current I, or R = V / I.

4. If the voltage across a resistor is 12 V and the current through it is 0.4 A, what is its resistance?

R = V / I = 12 V / 0.4 A = 30 Ω.

5. Why is it important to take multiple readings when measuring resistance?

Multiple readings reduce random errors and improve the accuracy and reliability of the calculated resistance.

Complete revision guide 3 of 5

Relationship Between Resistance, Length, and Cross-Sectional Area of a Metallic Wire

This note explains how the resistance of a metallic wire depends on its length and cross-sectional area, including the physical reasons behind these relationships and their practical implications in electrical circuits.

Syllabus source

Section 3, Topic 4.2.4, page 29, objective 4.2.4.3

Open source document ↗

What you should be able to do

  • ✓Understand that resistance increases with increasing length of a wire.
  • ✓Understand that resistance decreases with increasing cross-sectional area of a wire.
  • ✓Explain qualitatively why these relationships occur based on electron flow and collisions.
  • ✓Recognise the role of wire dimensions in designing electrical circuits.
1

Definition of Resistance

Resistance is a measure of how much a material opposes the flow of electric current. It is a scalar quantity measured in ohms (Ω). A higher resistance means less current flows for a given potential difference across the material.

In metallic wires, resistance arises because free electrons collide with fixed metal ions as they move through the wire, losing energy and slowing down the current flow.

  • Resistance (R) is measured in ohms (Ω).
  • It quantifies opposition to current flow.
  • Caused by collisions between electrons and metal ions.
2

Effect of Length on Resistance

The resistance of a metallic wire is directly proportional to its length. This means that if the length of the wire doubles, its resistance also doubles.

Physically, a longer wire contains more metal ions, so electrons collide more frequently, increasing resistance.

For example, a 2 m wire has twice the resistance of a 1 m wire made of the same material and thickness.

  • Resistance ∝ Length (R ∝ L).
  • Longer wire → more collisions → higher resistance.
  • Doubling length doubles resistance.
3

Effect of Cross-Sectional Area on Resistance

Resistance is inversely proportional to the cross-sectional area of the wire. A wire with a larger cross-sectional area has lower resistance.

This is because a thicker wire provides more paths for electrons to flow, reducing the chance of collisions and allowing more current to pass.

For example, doubling the cross-sectional area halves the resistance, assuming length and material remain constant.

  • Resistance ∝ 1 / Cross-sectional area (R ∝ 1/A).
  • Thicker wire → more electron paths → lower resistance.
  • Doubling area halves resistance.
4

Qualitative Relationship and Formula

Combining these relationships, resistance depends on both length and cross-sectional area as:

R ∝ L / A, where R is resistance, L is length, and A is cross-sectional area.

This means resistance increases with length and decreases with cross-sectional area for a wire of uniform material and temperature.

  • Resistance increases with length.
  • Resistance decreases with cross-sectional area.
  • R ∝ L / A (qualitative relationship).
5

Physical Explanation and Practical Implications

Electrons moving through a wire collide with metal ions, losing energy and causing resistance.

Longer wires have more ions to collide with, increasing resistance.

Thicker wires have more space for electrons to flow, reducing collisions and resistance, similar to how a wider pipe allows more water flow with less friction loss.

  • Resistance caused by electron-ion collisions.
  • Longer wire → more collisions → higher resistance.
  • Thicker wire → more flow paths → lower resistance.
  • Important for designing circuits to minimise energy loss.

At-a-glance summary

Comparison table

StepPhysics DetailEvidenceExam Use
Length effectResistance increases with length because electrons collide moreDoubling length doubles resistance in wireState and explain resistance-length relationship
Cross-sectional area effectResistance decreases with larger area due to more electron pathsDoubling area halves resistanceDescribe resistance-area relationship
Combined relationshipResistance proportional to length divided by areaR ∝ L/A for uniform wireQualitatively describe resistance dependence
Physical causeElectron collisions with metal ions cause resistanceMore collisions in longer/thinner wiresExplain why resistance changes with wire dimensions

Active recall

Quick check

1. What happens to the resistance if the length of a metallic wire is doubled?

The resistance doubles because resistance is directly proportional to length.

2. How does increasing the cross-sectional area of a wire affect its resistance?

Resistance decreases because it is inversely proportional to cross-sectional area.

3. Why does a longer wire have more resistance?

Because electrons collide with more metal ions over a longer distance, increasing resistance.

4. If a wire’s cross-sectional area is halved, what happens to its resistance?

The resistance doubles since resistance is inversely proportional to cross-sectional area.

Complete revision guide 4 of 5

Current-Voltage Characteristics of Resistors, Filament Lamps, and Diodes

This note explains the current-voltage (I-V) characteristics of three electrical components: resistors with constant resistance, filament lamps, and diodes. It covers the shape of their I-V graphs, the physical reasons behind these shapes, and how to interpret and sketch these characteristics.

Syllabus source

Section 3, Topic 4.2.4, page 29, objective 4.2.4.4

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What you should be able to do

  • ✓Understand and sketch the I-V characteristic of a resistor with constant resistance.
  • ✓Understand and sketch the I-V characteristic of a filament lamp and explain its non-linear behaviour.
  • ✓Understand and sketch the I-V characteristic of a diode and explain its rectifying behaviour.
1

Introduction to Current-Voltage Characteristics

The current-voltage (I-V) characteristic of an electrical component is a graph showing how the current (I, in amperes, A) flowing through the component varies with the potential difference (voltage, V, in volts, V) across it.

The shape of the I-V graph reveals important information about the component's electrical behaviour and resistance.

The voltage is plotted on the horizontal (x) axis and the current on the vertical (y) axis.

  • Voltage (V) on x-axis, Current (I) on y-axis.
  • Gradient of I-V graph = 1 / resistance (R) for ohmic components.
  • Non-linear graphs indicate changing resistance.
2

I-V Characteristics of a Resistor with Constant Resistance

A resistor with constant resistance obeys Ohm's Law, which states that the current through the resistor is directly proportional to the voltage across it, provided the temperature remains constant.

Mathematically, this is expressed as V = IR, where R is the resistance in ohms (Ω).

The I-V graph for such a resistor is a straight line passing through the origin, indicating a constant resistance.

  • Ohm's Law: V = IR
  • Graph is a straight line through origin.
  • Gradient = 1/R (steeper line means lower resistance).
3

I-V Characteristics of a Filament Lamp

A filament lamp does not have a constant resistance because its filament heats up as current flows through it.

As the filament temperature increases, its resistance increases due to increased atomic vibrations that impede electron flow.

The I-V graph is a curve that starts steep (low resistance at low temperature) and gradually flattens as voltage and current increase, showing a non-linear relationship.

  • Resistance increases with temperature.
  • Graph is a curve, not a straight line.
  • At low voltage, resistance is low; at high voltage, resistance is higher.
4

I-V Characteristics of a Diode

A diode allows current to flow primarily in one direction and blocks it in the opposite direction.

In the forward direction, the diode shows very little current until a threshold voltage (about 0.6–0.7 V for silicon diodes) is reached.

After this threshold, current increases rapidly with voltage, producing a steep curve on the I-V graph in the forward direction, while in the reverse direction, current is almost zero (except for a tiny leakage current).

  • Current flows only after threshold voltage (~0.6 V for silicon).
  • Graph shows almost zero current below threshold.
  • Current in reverse direction is negligible.
5

Sketching and Interpreting I-V Graphs

To sketch the I-V graph for each component, label the axes with voltage (V) on the x-axis and current (A) on the y-axis.

For the resistor, draw a straight line through the origin with constant gradient.

For the filament lamp, draw a curve starting steep near the origin and flattening as voltage increases, showing increasing resistance with temperature rise due to heating of the filament wire (usually tungsten). The resistance increases because the filament's atoms vibrate more at higher temperatures, scattering electrons more and reducing current increase rate relative to voltage increase (non-ohmic behaviour). For the diode, draw a graph with almost zero current along the x-axis in the negative voltage region (reverse bias), and in the positive voltage region (forward bias), a flat line near zero current until the threshold voltage, then a sharp rise in current beyond this point.

  • Label axes: Voltage (V), Current (A).
  • Resistor: straight line through origin.
  • Filament lamp: curve flattening at higher voltages.
  • Diode: near zero current until threshold voltage, then sharp increase.

At-a-glance summary

Comparison table

ComponentI-V Graph ShapePhysical ExplanationResistance Behaviour
ResistorStraight line through originConstant resistance; obeys Ohm's LawResistance is constant
Filament LampNon-linear curve, steep at low voltage, flattening at high voltageResistance increases with temperature as filament heats upResistance increases with current/temperature
DiodeAlmost zero current until threshold voltage, then sharp increase in forward direction; negligible current in reverseAllows current flow only after overcoming potential barrier; rectifying behaviourResistance very high below threshold, then decreases sharply
Diode (reverse bias)Flat near zero current (reverse leakage current negligible)Blocks current flow in reverse directionResistance very high

Active recall

Quick check

1. What is the shape of the I-V graph for a resistor with constant resistance?

A straight line through the origin, showing current is directly proportional to voltage.

2. Why does the filament lamp's I-V graph curve and flatten at higher voltages?

Because the filament heats up as current increases, increasing its resistance and causing a non-linear relationship between current and voltage.

3. At approximately what voltage does a silicon diode start to conduct significantly in the forward direction?

About 0.6 to 0.7 volts, known as the threshold or cut-in voltage.

4. What happens to the current through a diode when the voltage is reversed?

The current is almost zero because the diode blocks current flow in the reverse direction.

Complete revision guide 5 of 5

Resistance in Metallic Conductors: Relationship with Length and Cross-Sectional Area

This note explains how the electrical resistance of a metallic conductor depends on its length and cross-sectional area, including the mathematical relationships, physical reasoning, and practical implications for circuits.

Syllabus source

Section 3, Topic 4.2.4, page 29, objective 4.2.4.5

Open source document ↗

What you should be able to do

  • ✓Understand that resistance is directly proportional to the length of a metallic conductor.
  • ✓Understand that resistance is inversely proportional to the cross-sectional area of a metallic conductor.
  • ✓Apply these proportionalities to solve problems involving resistance, length, and area.
  • ✓Explain the physical reasons why length and cross-sectional area affect resistance.
  • ✓Use the formula R ∝ L/A to compare resistances of different conductors.
1

Definition of Resistance and Its Physical Meaning

Resistance (R) is a measure of how much a conductor opposes the flow of electric current. It is measured in ohms (Ω). When a potential difference (voltage) is applied across a conductor, the current that flows depends on the resistance according to Ohm's law (V = IR).

Resistance arises because free electrons moving through the metal collide with fixed ions in the lattice, losing energy and slowing down. The more collisions, the higher the resistance.

  • Resistance is measured in ohms (Ω).
  • It quantifies opposition to current flow.
  • Caused by collisions between electrons and metal ions.
2

Relationship Between Resistance and Length

The resistance of a metallic conductor is directly proportional to its length (L). This means that if the length of the conductor doubles, its resistance also doubles.

Physically, a longer wire means electrons have to travel a greater distance through the metal lattice, encountering more ions and thus more collisions, increasing resistance.

Mathematically, this is expressed as: R ∝ L, or R = ρ (L/A), where ρ is the resistivity and A is the cross-sectional area (explained in the next section).

  • Resistance increases as length increases.
  • Doubling length doubles resistance.
  • Longer path means more collisions for electrons.
3

Relationship Between Resistance and Cross-Sectional Area

Resistance is inversely proportional to the cross-sectional area (A) of the conductor. This means that if the cross-sectional area doubles, the resistance halves.

A larger cross-sectional area provides more pathways for electrons to flow, reducing the overall resistance.

Mathematically, this is expressed as: R ∝ 1/A, or R = ρ (L/A).

  • Resistance decreases as cross-sectional area increases.
  • Doubling area halves resistance.
  • More area means more paths for current.
4

Combined Relationship and Resistivity

Combining the two proportionalities, resistance is proportional to length divided by cross-sectional area: R ∝ L/A.

The constant of proportionality is called resistivity (ρ), a property of the material, measured in ohm metres (Ω·m).

The full formula is: R = ρ (L/A). Resistivity depends on the material and temperature but is constant for a given material at a fixed temperature.

  • Resistance formula: R = ρ (L/A).
  • Resistivity ρ is material-dependent, units Ω·m.
  • Formula allows calculation of resistance from dimensions and material.
5

Applying the Relationships: Worked Example

Example: Calculate the resistance of a copper wire 2.0 m long with a cross-sectional area of 1.0 mm². The resistivity of copper is 1.7 × 10⁻⁸ Ω·m.

Step 1: Convert area to m²: 1.0 mm² = 1.0 × 10⁻⁶ m².

Step 2: Use formula R = ρ (L/A) = (1.7 × 10⁻⁸) × (2.0) / (1.0 × 10⁻⁶) = 3.4 × 10⁻² Ω = 0.034 Ω.

  • Convert units carefully.
  • Substitute values into R = ρ (L/A).
  • Calculate and express answer with correct units.

At-a-glance summary

Comparison table

StepPhysics DetailEvidenceExam Use
Length effectResistance ∝ length; longer wire means more collisionsExperiments measuring resistance of wires of different lengthsCalculate resistance changes when length varies
Cross-sectional area effectResistance ∝ 1/area; thicker wire has lower resistanceMeasurements of resistance for wires with different thicknessesSolve problems involving area and resistance
FormulaR = ρ (L/A) combines both effectsUse of resistivity values for materialsApply formula to find resistance or dimensions
Physical causeElectron collisions with ions increase with length; more paths reduce resistanceMicroscopic model of conductionExplain resistance changes qualitatively

Active recall

Quick check

1. If the length of a wire doubles, what happens to its resistance?

The resistance doubles because resistance is directly proportional to length.

2. How does increasing the cross-sectional area of a wire affect its resistance?

Resistance decreases because it is inversely proportional to cross-sectional area.

3. Write the formula relating resistance, length, cross-sectional area, and resistivity.

R = ρ (L/A), where R is resistance, ρ is resistivity, L is length, and A is cross-sectional area.

4. Calculate the resistance of a 3 m wire with cross-sectional area 2 mm² and resistivity 1.5 × 10⁻⁸ Ω·m.

Convert area: 2 mm² = 2 × 10⁻⁶ m²; R = (1.5 × 10⁻⁸) × 3 / (2 × 10⁻⁶) = 2.25 × 10⁻² Ω = 0.0225 Ω.

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