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Cambridge IGCSE Chemistry revision notes

Extraction of metals Revision Notes

Cambridge IGCSE revision notes for Extraction of metals.

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Extraction of metals

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Complete revision guide 1 of 5

Influence of Reactivity on the Difficulty of Extracting Metals from Their Ores

The position of a metal in the reactivity series determines the method and difficulty of its extraction from ores. Highly reactive metals form stable compounds requiring energy-intensive methods like electrolysis, while less reactive metals can be extracted by simpler chemical reduction or heating.

Syllabus source

Section 3, Topic 9.6, page 28, objective 9.6.1

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What you should be able to do

  • ✓Understand the reactivity series and its relation to metal extraction.
  • ✓Explain why metals higher in the reactivity series are harder to extract.
  • ✓Describe extraction methods suitable for metals of different reactivities.
  • ✓Write balanced chemical equations for typical extraction reactions.
  • ✓Recognise the practical implications of metal reactivity on extraction techniques.
1

The Reactivity Series and Metal Stability

The reactivity series ranks metals according to their tendency to lose electrons and form positive ions (cations). Metals higher in the series, such as potassium, sodium, calcium, and aluminium, are more reactive and form more stable compounds (ores). This stability means these metals are chemically bonded strongly to other elements, making them harder to extract.

Less reactive metals like copper, silver, and gold form less stable compounds or occur in native form, making extraction easier. The position in the reactivity series directly influences the choice of extraction method and the energy required.

  • Reactivity series orders metals by reactivity: K > Na > Ca > Mg > Al > Zn > Fe > Pb > Cu > Ag > Au.
  • Higher reactivity means stronger bonding in ores and greater difficulty in extraction.
  • Lower reactivity metals often occur as native metals or in easily reduced ores.
2

Extraction Methods Related to Reactivity

Metals low in the reactivity series, such as copper, silver, and gold, can be extracted by simple heating or chemical reduction because their compounds are less stable.

Metals of intermediate reactivity, like iron and zinc, are commonly extracted by reduction with carbon (coke). Carbon acts as a reducing agent, removing oxygen from metal oxides to yield the metal.

Highly reactive metals, such as aluminium, calcium, sodium, and potassium, cannot be extracted by carbon reduction because their oxides are too stable. Instead, these metals require electrolysis of molten compounds to be extracted.

  • Low reactivity metals: extraction by heating or chemical reduction.
  • Intermediate reactivity metals: extraction by reduction with carbon.
  • High reactivity metals: extraction by electrolysis of molten ores.
3

Example: Extraction of Iron and Aluminium

Iron, moderately reactive, is extracted from iron(III) oxide (Fe2O3) by reduction with carbon monoxide in a blast furnace.

The reaction is: Fe2O3(s) + 3CO(g) → 2Fe(l) + 3CO2(g)

Aluminium, highly reactive, is extracted by electrolysis of molten aluminium oxide (Al2O3) dissolved in cryolite to lower its melting point. Carbon electrodes are used, and the reactions at the electrodes are: At cathode: Al3+(l) + 3e− → Al(l) At anode: 2O2−(l) → O2(g) + 4e−

  • Iron extraction uses carbon monoxide reduction at ~1500°C.
  • Aluminium extraction requires electrolysis due to high reactivity.
  • Electrolysis is energy-intensive but necessary for reactive metals.
4

Balanced Equations and Observations

Reduction of iron(III) oxide by carbon monoxide: Fe2O3(s) + 3CO(g) → 2Fe(l) + 3CO2(g)

Electrolysis of aluminium oxide: At cathode: Al3+(l) + 3e− → Al(l) (molten aluminium forms) At anode: 2O2−(l) → O2(g) + 4e− (oxygen gas bubbles observed)

Observations during extraction include the formation of molten metal, gas evolution (CO2 or O2), and slag formation to remove impurities.

  • Iron extraction produces molten iron and carbon dioxide gas.
  • Aluminium electrolysis produces molten aluminium and oxygen gas bubbles.
  • Slag forms from impurities and floats on molten metal.
5

Worked Example: Explaining Extraction Difficulty

Consider sodium (Na) and iron (Fe). Sodium is higher in the reactivity series than iron. Sodium forms very stable compounds like sodium chloride or sodium oxide, which cannot be reduced by carbon.

Therefore, sodium extraction requires electrolysis of molten sodium chloride.

Iron oxide is less stable and can be reduced by carbon monoxide in a blast furnace, a less energy-intensive method than electrolysis.

  • Sodium extraction: electrolysis of molten NaCl.
  • Iron extraction: reduction of Fe2O3 by CO.
  • Higher reactivity metals require more energy-intensive extraction.

At-a-glance summary

Comparison table

Metal ReactivityExtraction MethodChemical DetailEnergy Requirement
High (e.g. Na, K, Al)ElectrolysisIonic compounds melted; ions discharged at electrodesVery high energy input
Medium (e.g. Fe, Zn)Reduction with carbonMetal oxides reduced by CO or CModerate energy input
Low (e.g. Cu, Ag, Au)Heating or chemical reductionLess stable compounds or native metalsLow energy input
Very low (e.g. Au)Native metal extractionNo chemical extraction neededMinimal energy

Active recall

Quick check

1. Why do highly reactive metals require electrolysis for extraction?

Because their compounds are very stable and cannot be reduced by carbon or other chemical reducing agents, so electrical energy is needed to separate the metal ions.

2. Write the balanced equation for the reduction of iron(III) oxide by carbon monoxide.

Fe2O3(s) + 3CO(g) → 2Fe(l) + 3CO2(g)

3. What observation indicates oxygen gas is produced during aluminium extraction?

Bubbles of colourless gas form at the carbon anode, which is oxygen gas.

4. Explain why gold is easier to extract than aluminium.

Gold is less reactive and often found as native metal, so it requires little or no chemical extraction, whereas aluminium forms stable compounds requiring electrolysis.

Complete revision guide 2 of 5

Extraction of Iron from Hematite Using a Blast Furnace

This note details the chemical and physical processes involved in extracting iron from hematite ore in a blast furnace, covering coke combustion, carbon dioxide conversion, iron oxide reduction, limestone decomposition, and slag formation.

Syllabus source

Section 3, Topic 9.6, page 28, objective 9.6.2

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What you should be able to do

  • ✓Understand the role of coke combustion in providing heat and producing carbon dioxide.
  • ✓Explain how carbon dioxide is converted to carbon monoxide within the blast furnace.
  • ✓Describe the reduction of iron(III) oxide by carbon monoxide to produce iron.
  • ✓Outline the thermal decomposition of calcium carbonate to calcium oxide and carbon dioxide.
  • ✓Explain how slag is formed from calcium oxide and impurities to remove them from molten iron.
1

1. Combustion of Coke to Generate Heat and Carbon Dioxide

In the blast furnace, coke, a form of carbon, is burnt in the presence of hot air to generate the high temperatures (around 1500°C) necessary for the extraction of iron. This combustion reaction produces carbon dioxide and releases heat.

The reaction is: C(s) + O2(g) → CO2(g) (combustion of carbon)

This exothermic reaction maintains the furnace temperature and produces carbon dioxide gas, which plays a further role in the extraction process. The coke also acts as a reducing agent later in the furnace.

  • Coke is mainly carbon and burns in oxygen from hot air blast.
  • Produces carbon dioxide and heat to maintain furnace temperature.
  • Reaction: C + O2 → CO2 (no symbol equation required but useful for understanding).
2

2. Conversion of Carbon Dioxide to Carbon Monoxide

The carbon dioxide formed in the upper part of the furnace reacts with more coke at high temperatures to form carbon monoxide. This reaction is endothermic and occurs at around 1000°C.

The carbon monoxide formed is the main reducing agent that converts iron(III) oxide to iron.

The reaction is: CO2(g) + C(s) → 2CO(g) (carbon dioxide reacts with coke to form carbon monoxide)

  • CO2 reacts with excess coke to produce CO gas.
  • CO is a more effective reducing agent than CO2.
  • This reaction helps maintain a supply of CO for iron oxide reduction.
3

3. Reduction of Iron(III) Oxide by Carbon Monoxide

Hematite ore contains iron(III) oxide (Fe2O3). In the blast furnace, carbon monoxide reduces iron(III) oxide to molten iron by removing oxygen atoms.

This reduction occurs in the middle to lower parts of the furnace where temperatures are suitable for the reaction.

The reaction is: Fe2O3(s) + 3CO(g) → 2Fe(l) + 3CO2(g) (reduction of iron oxide to iron)

  • CO removes oxygen from Fe2O3, producing iron and CO2.
  • Molten iron collects at the bottom of the furnace.
  • CO2 formed can cycle back to react with coke, sustaining CO production.
4

4. Thermal Decomposition of Calcium Carbonate to Calcium Oxide

Limestone (calcium carbonate, CaCO3) is added to the blast furnace to remove impurities from the ore.

At high temperatures, calcium carbonate thermally decomposes to calcium oxide and carbon dioxide.

The reaction is: CaCO3(s) → CaO(s) + CO2(g) (thermal decomposition of limestone)

  • Limestone decomposes at furnace temperatures (~900°C).
  • Produces calcium oxide, which reacts with impurities.
  • CO2 released can contribute to CO formation.
5

5. Formation of Slag from Calcium Oxide and Impurities

The calcium oxide produced reacts with silica (SiO2), an impurity present in the ore, to form calcium silicate (CaSiO3), known as slag.

Slag is molten and less dense than iron, so it floats on top and can be removed easily.

This process removes impurities and protects the iron from contamination.

  • CaO reacts with SiO2 impurities to form slag (CaSiO3).
  • Slag floats on molten iron and is removed separately.
  • Slag formation improves iron purity and furnace efficiency.

At-a-glance summary

Comparison table

StepChemical DetailObservation/EvidenceExam Use
Combustion of cokeC + O2 → CO2; exothermicHeat generated, CO2 gas producedExplain heat source and CO2 formation
Conversion of CO2 to COCO2 + C → 2CO; endothermicCO gas formed, essential reducing agentDescribe CO role in reduction
Reduction of Fe2O3Fe2O3 + 3CO → 2Fe + 3CO2Molten iron produced, CO2 gas releasedOutline iron formation and oxygen removal
Decomposition of CaCO3CaCO3 → CaO + CO2CO2 gas released, CaO formedExplain limestone role and CO2 source
Formation of slagCaO + SiO2 → CaSiO3Molten slag floats on ironDescribe impurity removal and slag

Active recall

Quick check

1. What gas is produced when coke burns in the blast furnace?

Carbon dioxide (CO2) is produced when coke combusts with oxygen.

2. Which gas reduces iron(III) oxide to iron in the blast furnace?

Carbon monoxide (CO) reduces iron(III) oxide to iron.

3. What happens to calcium carbonate in the blast furnace?

Calcium carbonate thermally decomposes to calcium oxide and carbon dioxide.

4. Why is slag formed during iron extraction?

Slag forms when calcium oxide reacts with silica impurities, removing them from molten iron.

Complete revision guide 3 of 5

Extraction of Aluminium from Bauxite by Electrolysis

Bauxite is the primary ore of aluminium. Aluminium is extracted from purified bauxite by electrolysis of molten aluminium oxide dissolved in cryolite.

Syllabus source

Section 3, Topic 9.6, page 28, objective 9.6.3

Open source document ↗

What you should be able to do

  • ✓Identify bauxite as the main ore of aluminium.
  • ✓Understand that aluminium is extracted by electrolysis.
  • ✓Describe the electrolysis process used to obtain aluminium from aluminium oxide.
1

Bauxite as the Primary Ore of Aluminium

Bauxite is the main ore from which aluminium is extracted. It is a mixture of aluminium oxides and hydroxides, primarily containing aluminium oxide (Al₂O₃) along with impurities such as iron oxides and silica.

Bauxite is mined from open pits and then purified to obtain aluminium oxide, also called alumina, which is the compound used in the extraction process.

The purification process removes impurities but is not covered in detail here.

  • Bauxite contains aluminium oxide (Al₂O₃) and impurities.
  • It is the main source of aluminium metal.
  • Purification yields pure aluminium oxide for electrolysis.
2

Extraction of Aluminium by Electrolysis

Aluminium is extracted from aluminium oxide by electrolysis. Aluminium oxide has a very high melting point (over 2000°C), so it is dissolved in molten cryolite (Na₃AlF₆) to lower the melting point to about 900°C, making the process more energy-efficient.

An electric current is passed through the molten mixture, causing aluminium ions to gain electrons (reduction) at the cathode and oxygen ions to lose electrons (oxidation) at the anode.

  • Aluminium oxide is dissolved in molten cryolite to lower melting point.
  • Electrolysis involves passing electric current through molten mixture.
  • Aluminium ions are reduced to aluminium metal at the cathode.
  • Oxygen ions are oxidised to oxygen gas at the anode.
3

Electrolysis Cell and Reactions

The electrolytic cell contains a carbon-lined steel container acting as the cathode (negative electrode). Carbon anodes (positive electrodes) are immersed in the molten mixture.

At the cathode, aluminium ions (Al³⁺) gain electrons to form liquid aluminium, which collects at the bottom of the cell and is periodically removed.

At the anode, oxide ions (O²⁻) lose electrons to form oxygen gas, which reacts with the carbon anode to produce carbon dioxide, causing the anodes to gradually wear away and require replacement.

  • Cathode: carbon-lined container; anode: carbon blocks.
  • Cathode reaction: Al³⁺ + 3e⁻ → Al (liquid)
  • Anode reaction: 2O²⁻ → O₂ + 4e⁻
  • Oxygen reacts with carbon anode: C + O₂ → CO₂
  • Carbon anodes are consumed and replaced regularly.
4

Balanced Equations for Aluminium Extraction

The half-equations at the electrodes are: at the cathode, aluminium ions are reduced; at the anode, oxide ions are oxidised.

The overall reaction shows aluminium oxide decomposing into aluminium metal and oxygen gas, with carbon from the anode reacting to form carbon dioxide.

  • Cathode (reduction): Al³⁺ + 3e⁻ → Al
  • Anode (oxidation): 2O²⁻ → O₂ + 4e⁻
  • Anode carbon reaction: C + O₂ → CO₂
  • Overall reaction: 2Al₂O₃ + 3C → 4Al + 3CO₂
5

Practical and Industrial Considerations

The electrolysis process requires a large amount of electrical energy, making it expensive.

Cryolite lowers the melting point of aluminium oxide, reducing energy consumption.

Carbon anodes must be replaced regularly due to reaction with oxygen gas producing CO₂, which gradually consumes the anodes.

  • High electrical energy requirement.
  • Cryolite reduces melting point and energy use.
  • Carbon anodes wear out and need replacement.
  • Molten aluminium is periodically tapped from the cell.

At-a-glance summary

Comparison table

StepChemical DetailEvidenceExam Use
SourceBauxite contains aluminium oxide and impuritiesBauxite is the main ore of aluminiumIdentify bauxite as aluminium ore
PreparationPurification yields aluminium oxide (Al₂O₃)Aluminium oxide is used in electrolysisState aluminium oxide is electrolysed
ElectrolysisAluminium oxide dissolved in molten cryoliteLower melting point allows electrolysis at ~900°CExplain why cryolite is used
Cathode reactionAl³⁺ + 3e⁻ → Al (liquid aluminium)Aluminium metal forms at cathodeWrite cathode half-equation
Anode reaction2O²⁻ → O₂ + 4e⁻; O₂ reacts with C anode forming CO₂Carbon anodes consumed producing CO₂Write anode half-equation and overall reaction

Active recall

Quick check

1. What is the primary ore of aluminium?

Bauxite is the primary ore of aluminium.

2. Why is cryolite used in the extraction of aluminium?

Cryolite lowers the melting point of aluminium oxide, reducing the energy needed for electrolysis.

3. Write the half-equation at the cathode during aluminium extraction.

Al³⁺ + 3e⁻ → Al

4. What happens to the carbon anodes during electrolysis?

They react with oxygen to form carbon dioxide and gradually wear away, requiring replacement.

Complete revision guide 4 of 5

Extraction of Iron from Hematite: Key Symbol Equations

This revision note details the essential chemical reactions involved in extracting iron from hematite ore in a blast furnace. It covers the combustion of carbon to carbon dioxide, the formation of carbon monoxide, the reduction of iron(III) oxide to iron, the thermal decomposition of calcium carbonate, and the formation of slag through the reaction of calcium oxide with silicon dioxide. Balanced symbol equations are provided alongside explanations of their roles in the extraction process.

Syllabus source

Section 3, Topic 9.6, page 28, objective 9.6.4

Open source document ↗

What you should be able to do

  • ✓Understand and write balanced symbol equations for the main reactions in iron extraction from hematite.
  • ✓Explain the role of carbon and carbon monoxide in reducing iron ore to iron.
  • ✓Describe the thermal decomposition of calcium carbonate and its role in slag formation.
  • ✓Recognise the formation of slag as calcium silicate from calcium oxide and silicon dioxide.
1

1. Combustion of Carbon to Produce Carbon Dioxide

The extraction of iron from hematite (Fe2O3) in a blast furnace begins with the combustion of carbon (in the form of coke) in the presence of oxygen. This reaction provides the high temperatures required for the process and produces carbon dioxide (CO2).

The balanced symbol equation is: C(s) + O2(g) → CO2(g)

This exothermic reaction releases heat, raising the temperature inside the furnace to about 1500°C, necessary for subsequent reactions.

  • Carbon (coke) burns in oxygen to form carbon dioxide.
  • This reaction supplies heat for the blast furnace.
  • Equation: C + O2 → CO2
2

2. Formation of Carbon Monoxide from Carbon Dioxide and Carbon

The carbon dioxide produced reacts further with more carbon at high temperatures to form carbon monoxide (CO). This reaction is crucial because carbon monoxide acts as the reducing agent that converts iron ore into iron.

The balanced symbol equation is: C(s) + CO2(g) → 2CO(g)

Carbon monoxide is a more effective reducing agent than carbon dioxide and is essential for the reduction of iron(III) oxide.

  • Carbon dioxide reacts with carbon to form carbon monoxide.
  • Carbon monoxide reduces iron ore to iron.
  • Equation: C + CO2 → 2CO
3

3. Reduction of Iron(III) Oxide by Carbon Monoxide

The main chemical reaction in the extraction of iron is the reduction of iron(III) oxide (hematite) by carbon monoxide. This reaction removes oxygen from the ore, producing molten iron and carbon dioxide.

The balanced symbol equation is: Fe2O3(s) + 3CO(g) → 2Fe(l) + 3CO2(g)

Iron produced is molten due to the high temperature and collects at the bottom of the blast furnace. Carbon dioxide formed is recycled in the furnace reactions.

  • Iron(III) oxide is reduced to iron by carbon monoxide.
  • Oxygen is removed from the ore, producing CO2.
  • Equation: Fe2O3 + 3CO → 2Fe + 3CO2
4

4. Thermal Decomposition of Calcium Carbonate

Calcium carbonate (limestone) is added to the blast furnace to remove impurities. It thermally decomposes under heat to form calcium oxide (quicklime) and carbon dioxide.

The balanced symbol equation is: CaCO3(s) → CaO(s) + CO2(g)

This reaction occurs at temperatures above 825°C and provides calcium oxide for slag formation.

  • Limestone decomposes to calcium oxide and carbon dioxide.
  • Calcium oxide reacts with impurities to form slag.
  • Equation: CaCO3 → CaO + CO2
5

5. Formation of Slag by Reaction of Calcium Oxide with Silicon Dioxide

Silicon dioxide (sand) is an impurity in the iron ore. Calcium oxide reacts with silicon dioxide to form calcium silicate (slag), which is molten and less dense than iron, allowing it to be removed easily.

The balanced symbol equation is: CaO(s) + SiO2(s) → CaSiO3(l)

Slag floats on top of molten iron and can be drained off, preventing impurities from contaminating the iron.

  • Calcium oxide reacts with silicon dioxide to form slag (calcium silicate).
  • Slag removes impurities from molten iron.
  • Equation: CaO + SiO2 → CaSiO3

At-a-glance summary

Comparison table

StepChemical EquationRole in ExtractionExam Use
1. Combustion of CarbonC + O2 → CO2Produces heat and CO2 for further reactionsState the equation and explain heat generation
2. Formation of Carbon MonoxideC + CO2 → 2COGenerates CO, the reducing agentList equation and role of CO
3. Reduction of Iron OreFe2O3 + 3CO → 2Fe + 3CO2Reduces iron ore to iron metalWrite balanced equation and identify reducing agent
4. Decomposition of LimestoneCaCO3 → CaO + CO2Produces CaO for slag formationState equation and purpose of limestone
5. Formation of SlagCaO + SiO2 → CaSiO3Removes impurities as slagWrite equation and explain slag formation

Active recall

Quick check

1. Write the balanced symbol equation for the combustion of carbon in air.

C(s) + O2(g) → CO2(g)

2. Which gas reduces iron(III) oxide to iron in the blast furnace?

Carbon monoxide (CO)

3. Write the equation for the thermal decomposition of calcium carbonate.

CaCO3(s) → CaO(s) + CO2(g)

4. What is the chemical formula of the slag formed in the blast furnace?

Calcium silicate, CaSiO3

5. Balance the equation: Fe2O3 + ? CO → ? Fe + ? CO2

Fe2O3 + 3CO → 2Fe + 3CO2

Complete revision guide 5 of 5

Extraction of Aluminium from Purified Bauxite (Aluminium Oxide)

This note explains the industrial extraction of aluminium from purified bauxite (aluminium oxide) by electrolysis, detailing the role of cryolite, the necessity for regular replacement of carbon anodes, and the electrode reactions with ionic half-equations.

Syllabus source

Section 3, Topic 9.6, page 28, objective 9.6.5

Open source document ↗

What you should be able to do

  • ✓Understand why cryolite is added to aluminium oxide during electrolysis.
  • ✓Explain why carbon anodes must be replaced regularly in the extraction process.
  • ✓Write and interpret the ionic half-equations occurring at the cathode and anode during aluminium extraction.
1

Introduction to Aluminium Extraction

Aluminium is extracted from purified bauxite, which mainly consists of aluminium oxide (Al₂O₃). The extraction method used is electrolysis of molten aluminium oxide. Because aluminium is highly reactive, it cannot be extracted by reduction with carbon or other chemical reducing agents. Instead, electrolysis is used to separate aluminium metal from oxygen.

The process requires aluminium oxide to be molten to allow ions to move freely and conduct electricity. However, pure aluminium oxide has a very high melting point (about 2050°C), making direct electrolysis impractical due to the enormous energy required.

  • Aluminium is extracted by electrolysis of molten aluminium oxide.
  • High melting point of pure aluminium oxide makes direct electrolysis energy-intensive.
2

Role of Cryolite in Aluminium Extraction

To reduce the melting point and improve the conductivity of the electrolyte, aluminium oxide is dissolved in molten cryolite (Na₃AlF₆). Cryolite acts as a solvent and lowers the melting point of the mixture to about 900°C, which significantly reduces energy consumption and cost.

Cryolite also increases the electrical conductivity of the electrolyte, allowing the electrolysis to proceed efficiently at lower temperatures.

  • Cryolite lowers the melting point of aluminium oxide from ~2050°C to ~900°C.
  • Cryolite increases the electrical conductivity of the electrolyte.
  • Lower temperature reduces energy costs and equipment wear.
3

Carbon Anodes and Their Replacement

In the electrolytic cell, carbon anodes and cathodes are used. The carbon anodes serve as the positive electrodes where oxidation occurs. During electrolysis, oxygen ions (O²⁻) from aluminium oxide lose electrons at the anode and react with the carbon anode to form carbon dioxide gas.

This reaction consumes the carbon anodes, causing them to gradually wear away and require regular replacement to maintain the process.

The overall reaction at the anode is: 2O²⁻ → O₂ + 4e⁻, but the oxygen immediately reacts with the carbon anode: C + O₂ → CO₂.

  • Carbon anodes are oxidised and consumed during electrolysis.
  • Oxygen ions lose electrons and form oxygen gas at the anode.
  • Oxygen reacts with carbon anode producing CO₂ gas.
  • Anodes must be replaced regularly due to consumption.
4

Electrode Reactions and Ionic Half-Equations

During electrolysis, aluminium ions (Al³⁺) are reduced at the cathode (negative electrode) to form aluminium metal. Simultaneously, oxide ions (O²⁻) are oxidised at the anode (positive electrode) to form oxygen gas.

The ionic half-equations are: at the cathode, aluminium ions gain electrons to form aluminium atoms; at the anode, oxide ions lose electrons to form oxygen gas.

These half-equations are essential for understanding the electron transfer processes during extraction.

  • Cathode reaction (reduction): Al³⁺ + 3e⁻ → Al (liquid aluminium)
  • Anode reaction (oxidation): 2O²⁻ → O₂ + 4e⁻
  • Oxygen gas reacts with carbon anode producing CO₂ gas.
5

Summary of the Aluminium Extraction Process

The purified aluminium oxide is dissolved in molten cryolite to lower the melting point and increase conductivity. Electrolysis is carried out using carbon electrodes. Aluminium ions are reduced at the cathode to form molten aluminium, which collects at the bottom of the cell.

Oxide ions are oxidised at the carbon anode, producing oxygen gas that reacts with the carbon to form carbon dioxide, consuming the anode.

The process requires continuous replacement of carbon anodes and careful control of temperature and electrolyte composition to maintain efficiency.

  • Aluminium oxide dissolved in molten cryolite for electrolysis.
  • Aluminium metal forms at cathode and collects as molten aluminium.
  • Oxygen forms at anode and reacts with carbon anode producing CO₂.
  • Carbon anodes are consumed and replaced regularly.
  • Process operates at about 900°C for efficiency.

At-a-glance summary

Comparison table

StepChemical DetailEvidenceExam Use
Use of cryoliteLowers melting point of Al₂O₃ from 2050°C to ~900°CLower temperature electrolysis observedExplain energy efficiency and process feasibility
Carbon anode consumptionAnode oxidised to CO₂: C + O₂ → CO₂Anode mass decreases over timeExplain need for regular anode replacement
Cathode reactionAl³⁺ + 3e⁻ → AlMolten aluminium collected at cathodeWrite ionic half-equation for reduction
Anode reaction2O²⁻ → O₂ + 4e⁻; O₂ reacts with C to form CO₂Oxygen gas bubbles and CO₂ detectedWrite ionic half-equation for oxidation and explain anode consumption

Active recall

Quick check

1. Why is cryolite added to aluminium oxide during extraction?

Cryolite lowers the melting point of aluminium oxide and increases the electrical conductivity of the electrolyte, making electrolysis more energy-efficient.

2. Write the ionic half-equation occurring at the cathode during aluminium extraction.

Al³⁺ + 3e⁻ → Al

3. Why must carbon anodes be replaced regularly?

Because oxygen produced at the anode reacts with the carbon anode to form carbon dioxide, consuming the anode material.

4. Write the ionic half-equation occurring at the anode during aluminium extraction.

2O²⁻ → O₂ + 4e⁻

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